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-rw-r--r--arch/h8300/lib/moddivsi3.S73
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diff --git a/arch/h8300/lib/moddivsi3.S b/arch/h8300/lib/moddivsi3.S
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+/* SPDX-License-Identifier: GPL-2.0 */
+#include "libgcc.h"
+
+; numerator in A0/A1
+; denominator in A2/A3
+ .global __modsi3
+__modsi3:
+ PUSHP S2P
+ bsr modnorm
+ bsr __divsi3
+ mov.l er3,er0
+ bra exitdiv
+
+ .global __umodsi3
+__umodsi3:
+ bsr __udivsi3:16
+ mov.l er3,er0
+ rts
+
+ .global __divsi3
+__divsi3:
+ PUSHP S2P
+ bsr divnorm
+ bsr __udivsi3:16
+
+ ; examine what the sign should be
+exitdiv:
+ btst #3,S2L
+ beq reti
+
+ ; should be -ve
+ neg.l A0P
+
+reti:
+ POPP S2P
+ rts
+
+divnorm:
+ mov.l A0P,A0P ; is the numerator -ve
+ stc ccr,S2L ; keep the sign in bit 3 of S2L
+ bge postive
+
+ neg.l A0P ; negate arg
+
+postive:
+ mov.l A1P,A1P ; is the denominator -ve
+ bge postive2
+
+ neg.l A1P ; negate arg
+ xor.b #0x08,S2L ; toggle the result sign
+
+postive2:
+ rts
+
+;; Basically the same, except that the sign of the divisor determines
+;; the sign.
+modnorm:
+ mov.l A0P,A0P ; is the numerator -ve
+ stc ccr,S2L ; keep the sign in bit 3 of S2L
+ bge mpostive
+
+ neg.l A0P ; negate arg
+
+mpostive:
+ mov.l A1P,A1P ; is the denominator -ve
+ bge mpostive2
+
+ neg.l A1P ; negate arg
+
+mpostive2:
+ rts
+
+ .end