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|
set -o posix
fn() { foo=abc : ; typeset +x foo; printenv|grep ^foo=; }
fn
unset -v foo
unset -f fn
func1() {
var=1
var=2 : # or 'var=2 return', or another special builtin
unset -v var
echo $FUNCNAME: var = $var
}
func2() {
func1
unset -v var # bug: fails silently
}
func1
echo ${var+"BUG: still set 1"}
unset var
func2
echo ${var+"BUG: still set 2"}
unset -v var
unset -f func1 func2
fn() { foo=abc : ; typeset +x foo; echo -n 'inside: ' ; declare -p foo; }
fn
echo outside:
declare -p foo
unset -v foo
unset -f fn
func()
{
var=value declare -x var
echo -n 'inside: ' ; declare -p var
}
var=one
func
echo -n 'outside: ' ; declare -p var
unset -v var
unset -f func
# this will probably change behavior; export shouldn't behave like this when
# not in posix mode and the sequencing is probably wrong in posix mode. since
# export is a special builtin, the variable assignment should modify the
# global variable, leaving the local variable unchanged. all shells, including
# bash, modify the local variable; bash is the only one that propagates the
# value out to the calling environment. bash does that only when in posix
# mode.
func()
{
local var=inside
var=value export var
echo -n 'inside: ' ; declare -p var
}
var=outside
func
echo -n 'outside: ' ; declare -p var
unset -v var
unset -f func
func()
{
local var=local
var=global :
echo -n 'inside: ' ; declare -p var
}
var=outside
func
echo -n 'outside: ' ; declare -p var
unset -v var
unset -f func
# test whether or not temporary environment assignments are exported
# in posix mode
showfoo()
{
printf %s "foo=${foo-<unset>}"
echo -n ' environment foo='
printenv foo || echo
}
unset foo
showfoo
foo=foo showfoo
showfoo
unset -v foo
unset -f showfoo
|
