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-rw-r--r--gnulib-tests/infinity.h66
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diff --git a/gnulib-tests/infinity.h b/gnulib-tests/infinity.h
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+/* Macros for infinity.
+ Copyright (C) 2011-2018 Free Software Foundation, Inc.
+
+ This program is free software: you can redistribute it and/or modify
+ it under the terms of the GNU General Public License as published by
+ the Free Software Foundation; either version 3 of the License, or
+ (at your option) any later version.
+
+ This program is distributed in the hope that it will be useful,
+ but WITHOUT ANY WARRANTY; without even the implied warranty of
+ MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
+ GNU General Public License for more details.
+
+ You should have received a copy of the GNU General Public License
+ along with this program. If not, see <https://www.gnu.org/licenses/>. */
+
+
+/* Infinityf () returns a 'float' +Infinity. */
+
+/* The Microsoft MSVC 9 compiler chokes on the expression 1.0f / 0.0f.
+ The IBM XL C compiler on z/OS complains.
+ PGI 16.10 complains. */
+#if defined _MSC_VER || (defined __MVS__ && defined __IBMC__) || defined __PGI
+static float
+Infinityf ()
+{
+ static float zero = 0.0f;
+ return 1.0f / zero;
+}
+#else
+# define Infinityf() (1.0f / 0.0f)
+#endif
+
+
+/* Infinityd () returns a 'double' +Infinity. */
+
+/* The Microsoft MSVC 9 compiler chokes on the expression 1.0 / 0.0.
+ The IBM XL C compiler on z/OS complains.
+ PGI 16.10 complains. */
+#if defined _MSC_VER || (defined __MVS__ && defined __IBMC__) || defined __PGI
+static double
+Infinityd ()
+{
+ static double zero = 0.0;
+ return 1.0 / zero;
+}
+#else
+# define Infinityd() (1.0 / 0.0)
+#endif
+
+
+/* Infinityl () returns a 'long double' +Infinity. */
+
+/* The Microsoft MSVC 9 compiler chokes on the expression 1.0L / 0.0L.
+ The IBM XL C compiler on z/OS complains.
+ PGI 16.10 complains. */
+#if defined _MSC_VER || (defined __MVS__ && defined __IBMC__) || defined __PGI
+static long double
+Infinityl ()
+{
+ static long double zero = 0.0L;
+ return 1.0L / zero;
+}
+#else
+# define Infinityl() (1.0L / 0.0L)
+#endif