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???
Page 1
??? (???)
00/00/0000, 00:00:00
Page 1 / 99
IFNA Function
Result
TRUE
Sheet
Result
Description
1
TRUE
Simple IFNA formulas with local references and values
Function
Expected
Correct
FunctionString
Comment
#DIV/0!
#DIV/0!
TRUE
=IFNA(J2,K2)
#DIV/0!
AA
13
13
TRUE
=IFNA(J3,K3)
13
AA
2
2
TRUE
=IFNA(IF(0,1,2),4)
#DIV/0!
#DIV/0!
TRUE
=IFNA(IF(1/0,1,2),4)
4
4
TRUE
=IFNA(IF(NA(),1,2),4)
#DIV/0!
#DIV/0!
TRUE
=IFNA(IF(0,1,1/0),4)
4
4
TRUE
=IFNA(IF(0,1,NA()),4)
1
1
TRUE
{=IFNA(J9:J11,"Error!")}
1
Error!
Error!
TRUE
{=IFNA(J9:J11,"Error!")}
#N/A
3.14159265358979
3.14159265358979
TRUE
{=IFNA(J9:J11,"Error!")}
3.14159265358979
#VALUE!
Error
TRUE
=IFNA(IF("AA"+"BB","",0),"It was ERROR")
#VALUE!
Error
TRUE
=IFNA(IF("AA"+"BB","",0+0),"It was ERROR")
#DIV/0!
Error
TRUE
=IFNA(0/0,"alternative value")
#VALUE!
Error
TRUE
=IFNA(IF("foo"+1<=1,0,1),"alternative value")
Err:511
Error
TRUE
=IFNA(J16)
Err:511
Error
TRUE
=IFNA()
Err:511
Error
TRUE
=IFNA(J18)
Err:511
error
TRUE
=IFNA(,"A")
0
0
TRUE
=IFNA(0,"A")
2
2
TRUE
=IFNA(IF(0,1,2),4)
#DIV/0!
#DIV/0!
TRUE
=IFNA(IF(1/0,1,2),4)
4
4
TRUE
=IFNA(IF(NA(),1,2),4)
#DIV/0!
#DIV/0!
TRUE
=IFNA(IF(0,1,1/0),4)
4
4
TRUE
=IFNA(IF(0,1,NA()),4)
0
0
TRUE
=IFNA(J19,)
Err:511
0
=IFNA(,J19)
IFNA(J19,) return 0 =IFNA(,J19) return error→ compiler doesn't accept first argument to be omitted.
IFNASummary: Return X unless it is an NA, in which case return an alternative valueSyntax: IFNA( Any X ; Any Alternative )Returns: AnyConstraints: None.Semantics: Computes X. If ISNA(X) is true, return Alternative, else return X.Note: This is semantically equivalent to IF(ISNA(X); Alternative; X), except that X is only computed once.
4
O5