2016-06-25T07:16:38.437590147P0D1LibreOffice/5.1.3.2$Linux_X86_64 LibreOffice_project/10m0$Build-2 0 0 26393 9311 view1 2 8 0 0 0 0 2 0 0 0 0 0 100 60 true 4 16 0 0 0 0 2 0 0 0 0 0 100 60 true Sheet2 1185 0 100 60 false true true true 12632256 true true true true false false false 1270 1270 1 1 true 7 false false true true false false false 1270 1270 true true true true true true true false 12632256 false Lexmark-E352dn en US 3 1 true 1 true 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 false 0 Kč - Kč $ $( ) $- £ - £ £ - £ £ - £ £ - £ £ - £ ( ) ( ) £ - £ £ - £ Kč - Kč Kč - Kč Kč - Kč Kč - Kč € - € € - € € - € € - € - - € - € - € - - € - € - € : : : : $ ($ ) $ ($ ) $ ($ ) $ ($ ) ( ) - $ $ ( ) $ - ( ) - $ $ ( ) $ - Yes Yes No True True False On On Off € ( € ) \ \- \ \- \ \- \ \- \ \ - \ - - - \ \ - \ - - - - - - - - - € - € . / € - € ⌀ $ - $ ( ) - $ $( ) $- ( ) - $ € - € . . WAHR WAHR FALSCH / / - - - - : : : : : : / / : ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) - ( ) - ( ) - ( ) - . . : : : . . : - - - - € - € € - € € - € € - € % : : : : : : - $ - $ ??? Page 1 ??? (???) 00/00/0000, 00:00:00 Page 1 / 99 BITOR Function Result TRUE Sheet Result Description 1 TRUE Simple BITOR formulas with local references and values Function Expected Correct FunctionString Comment 14 14 TRUE =BITOR(6,10) 5 5 TRUE =BITOR(1,5) 25 29 29 TRUE =BITOR(13,25) Chyba:511 error TRUE =BITOR(25) Chyba:502 error TRUE =BITOR(-13,25) Chyba:511 error TRUE =BITOR(25) Chyba:502 error TRUE =BITOR(281474976710656,12) 25 25 TRUE =BITOR(25,) 0 0 TRUE =BITOR(J1,J2) 25 25 TRUE =BITOR(J2,J3) BITORSummary: Returns bitwise “or” of its parametersSyntax: BITOR( Integer X ; Integer Y )Returns: NumberConstraints: X ≥ 0, Y ≥ 0Semantics: Returns bitwise “or” of its parameters. In the result, each bit position is 1 if any of its parameters' bits at that position are also 1; else it is 0. 4 O5