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Lexmark-E352dn
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false
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???
Page 1
??? (???)
00/00/0000, 00:00:00
Page 1 / 99
GAMMA.INV Function
Result
TRUE
Sheet
Result
Description
1
TRUE
Simple GAMMA.INV formulas with local references and values
Function
Expected
Correct
FunctionString
Comment
Data
Description
0.068094
0.068014
0.067934
0.067854
0.067774
0.067694
0.067614
0.067534
1.6094379124341
1.6094379124341
TRUE
=GAMMA.INV(0.8,1,1)
0.068094
Probability associated with the gamma distribution
9
10
11
12
13
14
15
16
10.0000111914372
10.0000111914372
TRUE
=GAMMA.INV(I2,I3,I4)
9
Alpha parameter to the distribution
2
3
4
5
6
7
8
9
10.0000111914372
10.0000111914372
TRUE
=L5
2
Beta parameter to the distribution
17.2612321657702
17.2612321657702
TRUE
=M5
10.0000111914372
17.2612321657702
26.0781306737253
36.4785843328646
48.4859203591444
62.1199901195651
77.3979255239414
94.3346874759591
26.0781306737253
26.0781306737253
TRUE
=N5
36.4785843328646
36.4785843328646
TRUE
=O5
48.4859203591444
48.4859203591444000000
TRUE
=P5
62.1199901195651
62.1199901195651
TRUE
=Q5
62.1199901195651
62.1199901195651
TRUE
=Q5
77.3979255239414
77.3979255239414
TRUE
=R5
94.3346874759591
94.3346874759591
TRUE
=S5
0
0
TRUE
=GAMMA.INV(0,1,1)
Err:502
Err:502
TRUE
=GAMMA.INV(1,1,1)
Err:502
Err:502
TRUE
=GAMMA.INV(-0.8,1,1)
Err:502
Err:502
TRUE
=GAMMA.INV(0.8,0,1)
Err:502
Err:502
TRUE
=GAMMA.INV(0.8,1,0)
Err:502
Err:502
TRUE
=GAMMA.INV(0.8,-1,1)
Err:502
Err:502
TRUE
=GAMMA.INV(0.8,1,-1)