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+// SPDX-License-Identifier: GPL-2.0-or-later
+/*
+ * Inkscape::Algorithms::longest_common_suffix
+ *
+ * Authors:
+ * MenTaLguY <mental@rydia.net>
+ *
+ * Copyright (C) 2004 MenTaLguY
+ *
+ * Released under GNU GPL v2+, read the file 'COPYING' for more information.
+ */
+
+#ifndef SEEN_INKSCAPE_ALGORITHMS_LONGEST_COMMON_SUFFIX_H
+#define SEEN_INKSCAPE_ALGORITHMS_LONGEST_COMMON_SUFFIX_H
+
+#include <iterator>
+#include <functional>
+#include "util/list.h"
+
+namespace Inkscape {
+
+namespace Algorithms {
+
+/**
+ * Time costs:
+ *
+ * The case of sharing a common successor is handled in O(1) time.
+ *
+ * If \a a is the longest common suffix, then runs in O(len(rest of b)) time.
+ *
+ * Otherwise, runs in O(len(a) + len(b)) time.
+ */
+
+template <typename ForwardIterator>
+ForwardIterator longest_common_suffix(ForwardIterator a, ForwardIterator b,
+ ForwardIterator end)
+{
+ typedef typename std::iterator_traits<ForwardIterator>::value_type value_type;
+ return longest_common_suffix(a, b, end, std::equal_to<value_type>());
+}
+
+template <typename ForwardIterator, typename BinaryPredicate>
+ForwardIterator longest_common_suffix(ForwardIterator a, ForwardIterator b,
+ ForwardIterator end, BinaryPredicate pred)
+{
+ if ( a == end || b == end ) {
+ return end;
+ }
+
+ /* Handle in O(1) time the common cases of identical lists or tails. */
+ {
+ /* identical lists? */
+ if ( a == b ) {
+ return a;
+ }
+
+ /* identical tails? */
+ ForwardIterator tail_a(a);
+ ForwardIterator tail_b(b);
+ if ( ++tail_a == ++tail_b ) {
+ return tail_a;
+ }
+ }
+
+ /* Build parallel lists of suffixes, ordered by increasing length. */
+
+ using Inkscape::Util::List;
+ using Inkscape::Util::cons;
+ ForwardIterator lists[2] = { a, b };
+ List<ForwardIterator> suffixes[2];
+
+ for ( int i=0 ; i < 2 ; i++ ) {
+ for ( ForwardIterator iter(lists[i]) ; iter != end ; ++iter ) {
+ if ( iter == lists[1-i] ) {
+ // the other list is a suffix of this one
+ return lists[1-i];
+ }
+
+ suffixes[i] = cons(iter, suffixes[i]);
+ }
+ }
+
+ /* Iterate in parallel through the lists of suffix lists from shortest to
+ * longest, stopping before the first pair of suffixes that differs
+ */
+
+ ForwardIterator longest_common(end);
+
+ while ( suffixes[0] && suffixes[1] &&
+ pred(**suffixes[0], **suffixes[1]) )
+ {
+ longest_common = *suffixes[0];
+ ++suffixes[0];
+ ++suffixes[1];
+ }
+
+ return longest_common;
+}
+
+}
+
+}
+
+#endif /* !SEEN_INKSCAPE_ALGORITHMS_LONGEST_COMMON_SUFFIX_H */
+
+/*
+ Local Variables:
+ mode:c++
+ c-file-style:"stroustrup"
+ c-file-offsets:((innamespace . 0)(inline-open . 0)(case-label . +))
+ indent-tabs-mode:nil
+ fill-column:99
+ End:
+*/
+// vim: filetype=cpp:expandtab:shiftwidth=4:tabstop=8:softtabstop=4 :