1 files changed, 132 insertions, 0 deletions
diff --git a/svl/source/misc/lngmisc.cxx b/svl/source/misc/lngmisc.cxx
new file mode 100644
index 000000000..4224a1442
--- /dev/null
+++ b/svl/source/misc/lngmisc.cxx
@@ -0,0 +1,132 @@
+/* -*- Mode: C++; tab-width: 4; indent-tabs-mode: nil; c-basic-offset: 4 -*- */
+/*
+ * This file is part of the LibreOffice project.
+ *
+ * This Source Code Form is subject to the terms of the Mozilla Public
+ * License, v. 2.0. If a copy of the MPL was not distributed with this
+ * file, You can obtain one at http://mozilla.org/MPL/2.0/.
+ *
+ * This file incorporates work covered by the following license notice:
+ *
+ *   Licensed to the Apache Software Foundation (ASF) under one or more
+ *   contributor license agreements. See the NOTICE file distributed
+ *   with this work for additional information regarding copyright
+ *   ownership. The ASF licenses this file to you under the Apache
+ *   License, Version 2.0 (the "License"); you may not use this file
+ *   except in compliance with the License. You may obtain a copy of
+ *   the License at http://www.apache.org/licenses/LICENSE-2.0 .
+ */
+
+
+#include <svl/lngmisc.hxx>
+
+#include <comphelper/string.hxx>
+#include <rtl/ustrbuf.hxx>
+#include <tools/debug.hxx>
+
+namespace linguistic
+{
+    sal_Int32 GetNumControlChars(const OUString &rTxt)
+    {
+        sal_Int32 nCnt = 0;
+        for (sal_Int32 i = 0; i < rTxt.getLength(); ++i)
+            if (IsControlChar(rTxt[i]))
+                ++nCnt;
+        return nCnt;
+    }
+
+    bool RemoveHyphens(OUString &rTxt)
+    {
+        sal_Int32 n = rTxt.getLength();
+        rTxt = rTxt.replaceAll(OUStringChar(SVT_SOFT_HYPHEN), "");
+        rTxt = rTxt.replaceAll(OUStringChar(SVT_HARD_HYPHEN), "");
+        return n != rTxt.getLength();
+    }
+
+    bool RemoveControlChars(OUString &rTxt)
+    {
+        sal_Int32 nSize = rTxt.getLength() - GetNumControlChars(rTxt);
+        if(nSize == rTxt.getLength())
+            return false;
+
+        OUStringBuffer aBuf(nSize);
+        aBuf.setLength(nSize);
+        for (sal_Int32 i = 0, j = 0; i < rTxt.getLength() && j < nSize; ++i)
+            if (!IsControlChar(rTxt[i]))
+                aBuf[j++] = rTxt[i];
+
+        rTxt = aBuf.makeStringAndClear();
+        DBG_ASSERT(rTxt.getLength() == nSize, "GetNumControlChars returned a different number of control characters than were actually removed.");
+
+        return true;
+    }
+
+    bool ReplaceControlChars(OUString &rTxt)
+    {
+        // non breaking field character
+        static const char CH_TXTATR_INWORD = static_cast<char>(0x02);
+
+        // the resulting string looks like this:
+        // 1. non breaking field characters get removed
+        // 2. remaining control characters will be replaced by ' '
+
+        if (GetNumControlChars(rTxt) == 0)
+            return false;
+
+        sal_Int32 n = rTxt.getLength();
+
+        OUStringBuffer aBuf(n);
+        aBuf.setLength(n);
+
+        sal_Int32 j = 0;
+        for (sal_Int32 i = 0; i < n && j < n; ++i)
+        {
+            if (CH_TXTATR_INWORD == rTxt[i])
+                continue;
+
+            aBuf[j++] = IsControlChar(rTxt[i]) ? ' ' : rTxt[i];
+        }
+
+        aBuf.setLength(j);
+        rTxt = aBuf.makeStringAndClear();
+
+        return true;
+    }
+
+    OUString GetThesaurusReplaceText(const OUString &rText)
+    {
+        // The strings for synonyms returned by the thesaurus sometimes have some
+        // explanation text put in between '(' and ')' or a trailing '*'.
+        // These parts should not be put in the ReplaceEdit Text that may get
+        // inserted into the document. Thus we strip them from the text.
+
+        OUString aText(rText);
+
+        sal_Int32 nPos = aText.indexOf('(');
+        while (nPos >= 0)
+        {
+            sal_Int32 nEnd = aText.indexOf(')', nPos);
+            if (nEnd >= 0)
+            {
+                OUStringBuffer aTextBuf(aText);
+                aTextBuf.remove(nPos, nEnd - nPos + 1);
+                aText = aTextBuf.makeStringAndClear();
+            }
+            else
+                break;
+            nPos = aText.indexOf('(');
+        }
+
+        nPos = aText.indexOf('*');
+        if(nPos == 0)
+            return OUString();
+        else if(nPos > 0)
+            aText = aText.copy(0, nPos);
+
+        // remove any possible remaining ' ' that may confuse the thesaurus
+        // when it gets called with the text
+        return comphelper::string::strip(aText, ' ');
+    }
+} // namespace linguistic
+
+/* vim:set shiftwidth=4 softtabstop=4 expandtab: */