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/*
* Any copyright is dedicated to the Public Domain.
* http://creativecommons.org/licenses/publicdomain/
*/
//-----------------------------------------------------------------------------
var BUGNUMBER = 668024;
var summary =
'Array.prototype.splice, when it deletes elements, should make sure any ' +
'deleted but not visited elements are suppressed from subsequent enumeration';
print(BUGNUMBER + ": " + summary);
/**************
* BEGIN TEST *
**************/
var arr = [0, 1, 2, 3, 4, 5, , 7];
var seen = [];
var sawOneBeforeThree = true;
for (var p in arr)
{
if (p === "1")
{
// The order of enumeration of properties is unspecified, so technically,
// it would be kosher to enumerate "1" last, say, such that all properties
// in the array actually were enumerated, including an index which splice
// would delete. Don't flag that case as a failure. (SpiderMonkey doesn't
// do this, and neither do any of the other browser engines, but it is
// permissible behavior.)
if (seen.indexOf("3") >= 0)
{
sawOneBeforeThree = false;
break;
}
arr.splice(2, 3);
}
seen.push(p);
}
if (sawOneBeforeThree)
{
// ES5 12.6.4 states:
//
// If a property that has not yet been visited during enumeration is
// deleted, then it will not be visited.
//
// So if we haven't seen "3" by the time we see "1", the splice call above
// will delete "3", and therefore we must not see it.
assertEq(seen.indexOf("3"), -1);
}
/******************************************************************************/
if (typeof reportCompare === "function")
reportCompare(true, true);
print("Tests complete");
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