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// Copyright 2009 the Sputnik authors. All rights reserved.
// This code is governed by the BSD license found in the LICENSE file.
/*---
info: |
If pos is a value of Number type that is an integer, then the result of
x.charAt(pos) is equal to the result of x.substring(pos, pos+1)
es5id: 15.5.4.4_A4_T1
description: Compare results of x.charAt(pos) and x.substring(pos, pos+1)
---*/
//////////////////////////////////////////////////////////////////////////////
//CHECK#1
for (var i = 0; i < 6; i++) {
if ("ABC\u0041\u0042\u0043".charAt(i) !== "\u0041\u0042\u0043ABC".substring(i, i + 1)) {
throw new Test262Error('#' + i + ': "ABC\\u0041\\u0042\\u0043".charAt(' + i + ') === "\\u0041\\u0042\\u0043ABC".substring(' + i + ', ' + (i + 1) + '). Actual: "ABC\\u0041\\u0042\\u0043".charAt(' + i + ') ===' + ("ABC\u0041\u0042\u0043".charAt(i)));
}
}
//
//////////////////////////////////////////////////////////////////////////////
reportCompare(0, 0);
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