DateDiff Function /text/sbasic/shared/03030120.xhp
DateDiff function

DateDiff Function

Returns the number of date or time intervals between two given date values.
DateDiff (interval As String, date1 As Date, date2 As Date [, firstDayOfWeek As Integer [, firstWeekOfYear As Integer]]) As Double

Return value:

A number. interval - A string expression from the following table, specifying the date or time interval. date1, date2 - The two date values to be compared.
firstdayofweek: An optional parameter that specifies the starting day of a week. firstdayofweek value Explanation 0 Use system default value 1 Sunday (default) 2 Monday 3 Tuesday 4 Wednesday 5 Thursday 6 Friday 7 Saturday
firstweekofyear: An optional parameter that specifies the starting week of a year. firstweekofyear value Explanation 0 Use system default value 1 Week 1 is the week with January, 1st (default) 2 Week 1 is the first week containing four or more days of that year 3 Week 1 is the first week containing only days of the new year
Sub example_datediff MsgBox DateDiff("d", #1/1/2005#, #2005-12-31#) End Sub