- ( ) - - - - - £ - £ £ - £ £ - £ £ - £ £ - £ ( ) ( ) £ - £ £ - £ - - / / / / - - - - - - - - - - - - - Kč - - - - : : : : Yes Yes No True True False On On Off ¥€ ( ) - $ ($ ) - - - - - - - - € - - - - $ ($ ) $ ($ ) $ ($ ) ( ) - $ $ ( ) $ - $ $ ( ) $ - ( ) \ \- \ \- \ \- \ \- \ \ - \ - - - \ \ - \ - - - - - - - $ $( ) $- ( ) - $ $( ) $- ( ) - % % % % % % % % % % - - - - - - - - - - - - - - - % % % % % % $ ( $ ) % % - % - - - £ - £ £ - £ % - % DM - DM DM - DM DM - DM DM - DM - - DM - DM - DM - - DM - DM - DM Ouch! - - Error detected! - Result=0 - No Errordetection / / / / £ £ £ £ - - £ £ - - - £ £ - - DM - DM DM - DM DM - DM DM - DM DM - DM - tan aa - - : : : : - - / / - - - - : : : : : : / / : ( ) ( ) ( ) ( ) ( ) ( ) - : : : ( ) % ( ) - ( ) - ( ) - ( ) - . . : : : . . : - - - - - - - - : : : - - - - - - - - - - : : : : : : - - : - - - - - - - - - - - - % ??? Page 1 ??? (???) 00/00/0000, 00:00:00 Page 1 / 99 PERCENTRANK.EXC Function Result TRUE Sheet Result Description 1 TRUE Simple PERCENTRANK.EXC formulas with local references and values Function Expected Correct FunctionString Comment Data 0.001 1E+016 Data Data Data 0.6 0.6 TRUE =PERCENTRANK.EXC(I2:I5,3,4) 1 0.004 1E+016 1 13 1 0.6 0.6 TRUE =PERCENTRANK.EXC(I2:I5,3) 3 0.007 1E+016 2 12 2 0.874000 0.874 TRUE =PERCENTRANK.EXC(K1:K57,0.15) 2 0.01 1E+016 3 11 3 0.0172 0.0172 TRUE =PERCENTRANK.EXC(L1:L57,L45) 4 0.013 1E+016 6 8 6 0.75 0.75 TRUE =PERCENTRANK.EXC(I9:I11,I11,5) 0.016 1E+016 6 4 6 0.4 0.4 TRUE =PERCENTRANK.EXC(N2:N11,N6,1) 0.019 1E+016 6 3 6 0.189189189189189 0.189189189189189 TRUE =PERCENTRANK.EXC(I2:N11,K6,44) 0.022 1E+016 7 2 7 0.6 0.6 TRUE =PERCENTRANK.EXC({1,2,3,4}, 3, 2) -1 0.025 1E+016 8 1 8 0.6 0.6 TRUE =PERCENTRANK.EXC({1,2,3,4}, 3) 0 0.028 1E+016 9 1 9 0.7 0.7 TRUE =PERCENTRANK.EXC({1,2,3,4}, 3.5, 2) 1 0.031 1E+016 1 Formula Description R esult 0.655 0.655 TRUE =PERCENTRANK.EXC({7,8,9,20}, 12) 0.034 1E+016 Returns the rank of the value 7 from the array contained in A2:A10. 0.7 0.364 0.364 TRUE =PERCENTRANK.EXC(P2:P11,2) 0.037 1E+016 Returns the rank of the value 5.43 in the same array. 0.381 0.545 0.545 TRUE =PERCENTRANK.EXC(P2:P11,4) 0.04 1E+016 Returns the rank of the value 5.43 in the same array, displaying only 1 significant digit in the result (the default is 3). 0.3 0.636 0.636 TRUE =PERCENTRANK.EXC(P2:P11,8) 0.043 1E+016 0.568 0.568 TRUE =PERCENTRANK.EXC(P2:P11,5) 0.046 1E+016 0.577 0.577 TRUE =PERCENTRANK.EXC(P2:P11,5.4) 0.049 1E+016 1 1 TRUE =PERCENTRANK.EXC(I2,1,1) 0.052 1E+016 #VALUE! #VALUE! TRUE =PERCENTRANK.EXC(I2,-1,1) 0.055 1E+016 #VALUE! #VALUE! TRUE =PERCENTRANK.EXC(I2,0,1) 0.058 1E+016 Err:502 Err:502 TRUE =PERCENTRANK.EXC(I2,1,0) 0.061 1E+016 Err:502 Err:502 TRUE =PERCENTRANK.EXC(I2,1,-1) 0.064 1E+016 0.7 0.7 TRUE =PERCENTRANK.EXC(R2:R10, 7) 0.067 1E+016 0.381 0.381 TRUE =PERCENTRANK.EXC(R2:R10,5.43) 0.07 1E+016 0.4 0.4 TRUE =PERCENTRANK.EXC(R2:R10,5.43,1) 0.073 1E+016 0.076 1E+016 0.079 1E+016 0.082 1E+016 0.085 1E+016 0.088 1E+016 0.091 1E+016 0.094 1E+016 0.097 1E+016 0.1 1E+016 0.103 1E+016 0.106 1E+016 0.109 1E+016 0.112 1E+016 0.115 1E+016 0.118 1E+016 0.121 1E+016 0.124 1E+016 0.127 1E+016 0.13 1E+016 0.133 1E+016 0.136 1E+016 0.139 1E+016 0.142 1E+016 0.145 1E+016 0.148 1E+016 0.151 1.00000000000001E+016 0.154 1.00000000000001E+016 0.157 1.00000000000001E+016 0.16 1.00000000000001E+016 0.163 1.00000000000001E+016 0.166 1.00000000000001E+016 0.169 1.00000000000001E+016