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-rw-r--r--vendor/memchr/src/memmem/util.rs88
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+// These routines are meant to be optimized specifically for low latency as
+// compared to the equivalent routines offered by std. (Which may invoke the
+// dynamic linker and call out to libc, which introduces a bit more latency
+// than we'd like.)
+
+/// Returns true if and only if needle is a prefix of haystack.
+#[inline(always)]
+pub(crate) fn is_prefix(haystack: &[u8], needle: &[u8]) -> bool {
+ needle.len() <= haystack.len() && memcmp(&haystack[..needle.len()], needle)
+}
+
+/// Returns true if and only if needle is a suffix of haystack.
+#[inline(always)]
+pub(crate) fn is_suffix(haystack: &[u8], needle: &[u8]) -> bool {
+ needle.len() <= haystack.len()
+ && memcmp(&haystack[haystack.len() - needle.len()..], needle)
+}
+
+/// Return true if and only if x.len() == y.len() && x[i] == y[i] for all
+/// 0 <= i < x.len().
+///
+/// Why not just use actual memcmp for this? Well, memcmp requires calling out
+/// to libc, and this routine is called in fairly hot code paths. Other than
+/// just calling out to libc, it also seems to result in worse codegen. By
+/// rolling our own memcmp in pure Rust, it seems to appear more friendly to
+/// the optimizer.
+///
+/// We mark this as inline always, although, some callers may not want it
+/// inlined for better codegen (like Rabin-Karp). In that case, callers are
+/// advised to create a non-inlineable wrapper routine that calls memcmp.
+#[inline(always)]
+pub(crate) fn memcmp(x: &[u8], y: &[u8]) -> bool {
+ if x.len() != y.len() {
+ return false;
+ }
+ // If we don't have enough bytes to do 4-byte at a time loads, then
+ // fall back to the naive slow version.
+ //
+ // TODO: We could do a copy_nonoverlapping combined with a mask instead
+ // of a loop. Benchmark it.
+ if x.len() < 4 {
+ for (&b1, &b2) in x.iter().zip(y) {
+ if b1 != b2 {
+ return false;
+ }
+ }
+ return true;
+ }
+ // When we have 4 or more bytes to compare, then proceed in chunks of 4 at
+ // a time using unaligned loads.
+ //
+ // Also, why do 4 byte loads instead of, say, 8 byte loads? The reason is
+ // that this particular version of memcmp is likely to be called with tiny
+ // needles. That means that if we do 8 byte loads, then a higher proportion
+ // of memcmp calls will use the slower variant above. With that said, this
+ // is a hypothesis and is only loosely supported by benchmarks. There's
+ // likely some improvement that could be made here. The main thing here
+ // though is to optimize for latency, not throughput.
+
+ // SAFETY: Via the conditional above, we know that both `px` and `py`
+ // have the same length, so `px < pxend` implies that `py < pyend`.
+ // Thus, derefencing both `px` and `py` in the loop below is safe.
+ //
+ // Moreover, we set `pxend` and `pyend` to be 4 bytes before the actual
+ // end of of `px` and `py`. Thus, the final dereference outside of the
+ // loop is guaranteed to be valid. (The final comparison will overlap with
+ // the last comparison done in the loop for lengths that aren't multiples
+ // of four.)
+ //
+ // Finally, we needn't worry about alignment here, since we do unaligned
+ // loads.
+ unsafe {
+ let (mut px, mut py) = (x.as_ptr(), y.as_ptr());
+ let (pxend, pyend) = (px.add(x.len() - 4), py.add(y.len() - 4));
+ while px < pxend {
+ let vx = (px as *const u32).read_unaligned();
+ let vy = (py as *const u32).read_unaligned();
+ if vx != vy {
+ return false;
+ }
+ px = px.add(4);
+ py = py.add(4);
+ }
+ let vx = (pxend as *const u32).read_unaligned();
+ let vy = (pyend as *const u32).read_unaligned();
+ vx == vy
+ }
+}