From 218caa410aa38c29984be31a5229b9fa717560ee Mon Sep 17 00:00:00 2001
From: Daniel Baumann <daniel.baumann@progress-linux.org>
Date: Wed, 17 Apr 2024 14:19:13 +0200
Subject: Merging upstream version 1.68.2+dfsg1.

Signed-off-by: Daniel Baumann <daniel.baumann@progress-linux.org>
---
 .../rustc_error_codes/src/error_codes/E0792.md     | 60 ++++++++++++++++++++++
 1 file changed, 60 insertions(+)
 create mode 100644 compiler/rustc_error_codes/src/error_codes/E0792.md

(limited to 'compiler/rustc_error_codes/src/error_codes/E0792.md')

diff --git a/compiler/rustc_error_codes/src/error_codes/E0792.md b/compiler/rustc_error_codes/src/error_codes/E0792.md
new file mode 100644
index 000000000..bad2b5abf
--- /dev/null
+++ b/compiler/rustc_error_codes/src/error_codes/E0792.md
@@ -0,0 +1,60 @@
+A type alias impl trait can only have its hidden type assigned
+when used fully generically (and within their defining scope).
+This means
+
+```compile_fail,E0792
+#![feature(type_alias_impl_trait)]
+
+type Foo<T> = impl std::fmt::Debug;
+
+fn foo() -> Foo<u32> {
+    5u32
+}
+```
+
+is not accepted. If it were accepted, one could create unsound situations like
+
+```compile_fail,E0792
+#![feature(type_alias_impl_trait)]
+
+type Foo<T> = impl Default;
+
+fn foo() -> Foo<u32> {
+    5u32
+}
+
+fn main() {
+    let x = Foo::<&'static mut String>::default();
+}
+```
+
+
+Instead you need to make the function generic:
+
+```
+#![feature(type_alias_impl_trait)]
+
+type Foo<T> = impl std::fmt::Debug;
+
+fn foo<U>() -> Foo<U> {
+    5u32
+}
+```
+
+This means that no matter the generic parameter to `foo`,
+the hidden type will always be `u32`.
+If you want to link the generic parameter to the hidden type,
+you can do that, too:
+
+
+```
+#![feature(type_alias_impl_trait)]
+
+use std::fmt::Debug;
+
+type Foo<T: Debug> = impl Debug;
+
+fn foo<U: Debug>() -> Foo<U> {
+    Vec::<U>::new()
+}
+```
-- 
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