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### What it does
Checks for using `x.get(x.len() - 1)` instead of
`x.last()`.
### Why is this bad?
Using `x.last()` is easier to read and has the same
result.
Note that using `x[x.len() - 1]` is semantically different from
`x.last()`. Indexing into the array will panic on out-of-bounds
accesses, while `x.get()` and `x.last()` will return `None`.
There is another lint (get_unwrap) that covers the case of using
`x.get(index).unwrap()` instead of `x[index]`.
### Example
```
let x = vec![2, 3, 5];
let last_element = x.get(x.len() - 1);
```
Use instead:
```
let x = vec![2, 3, 5];
let last_element = x.last();
```
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