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+/* -*- indent-tabs-mode: nil; js-indent-level: 2 -*- */
+/* This Source Code Form is subject to the terms of the Mozilla Public
+ * License, v. 2.0. If a copy of the MPL was not distributed with this
+ * file, You can obtain one at http://mozilla.org/MPL/2.0/. */
+
+/*
+ * Date: 22 October 2001
+ *
+ * SUMMARY: Regression test for Bugzilla bug 105972:
+ * "/^.*?$/ will not match anything"
+ *
+ * See http://bugzilla.mozilla.org/show_bug.cgi?id=105972
+ */
+//-----------------------------------------------------------------------------
+var i = 0;
+var BUGNUMBER = 105972;
+var summary = 'Regression test for Bugzilla bug 105972';
+var cnEmptyString = '';
+var status = '';
+var statusmessages = new Array();
+var pattern = '';
+var patterns = new Array();
+var string = '';
+var strings = new Array();
+var actualmatch = '';
+var actualmatches = new Array();
+var expectedmatch = '';
+var expectedmatches = new Array();
+
+
+/*
+ * The bug: this match was coming up null in Rhino and SpiderMonkey.
+ * It should match the whole string. The reason:
+ *
+ * The * operator is greedy, but *? is non-greedy: it will stop
+ * at the simplest match it can find. But the pattern here asks us
+ * to match till the end of the string. So the simplest match must
+ * go all the way out to the end, and *? has no choice but to do it.
+ */
+status = inSection(1);
+pattern = /^.*?$/;
+string = 'Hello World';
+actualmatch = string.match(pattern);
+expectedmatch = Array(string);
+addThis();
+
+
+/*
+ * Leave off the '$' condition - here we expect the empty string.
+ * Unlike the above pattern, we don't have to match till the end of
+ * the string, so the non-greedy operator *? doesn't try to...
+ */
+status = inSection(2);
+pattern = /^.*?/;
+string = 'Hello World';
+actualmatch = string.match(pattern);
+expectedmatch = Array(cnEmptyString);
+addThis();
+
+
+/*
+ * Try '$' combined with an 'or' operator.
+ *
+ * The operator *? will consume the string from left to right,
+ * attempting to satisfy the condition (:|$). When it hits ':',
+ * the match will stop because the operator *? is non-greedy.
+ *
+ * The submatch $1 = (:|$) will contain the ':'
+ */
+status = inSection(3);
+pattern = /^.*?(:|$)/;
+string = 'Hello: World';
+actualmatch = string.match(pattern);
+expectedmatch = Array('Hello:', ':');
+addThis();
+
+
+/*
+ * Again, '$' combined with an 'or' operator.
+ *
+ * The operator * will consume the string from left to right,
+ * attempting to satisfy the condition (:|$). When it hits ':',
+ * the match will not stop since * is greedy. The match will
+ * continue until it hits $, the end-of-string boundary.
+ *
+ * The submatch $1 = (:|$) will contain the empty string
+ * conceived to exist at the end-of-string boundary.
+ */
+status = inSection(4);
+pattern = /^.*(:|$)/;
+string = 'Hello: World';
+actualmatch = string.match(pattern);
+expectedmatch = Array(string, cnEmptyString);
+addThis();
+
+
+
+
+//-----------------------------------------------------------------------------
+test();
+//-----------------------------------------------------------------------------
+
+
+
+function addThis()
+{
+ statusmessages[i] = status;
+ patterns[i] = pattern;
+ strings[i] = string;
+ actualmatches[i] = actualmatch;
+ expectedmatches[i] = expectedmatch;
+ i++;
+}
+
+
+function test()
+{
+ printBugNumber(BUGNUMBER);
+ printStatus (summary);
+ testRegExp(statusmessages, patterns, strings, actualmatches, expectedmatches);
+}