//! Tests for `__BindgenBitfieldUnit`. //! //! Note that bit-fields are allocated right to left (least to most significant //! bits). //! //! From the x86 PS ABI: //! //! ```c //! struct { //! int j : 5; //! int k : 6; //! int m : 7; //! }; //! ``` //! //! ```ignore //! +------------------------------------------------------------+ //! | | | | | //! | padding | m | k | j | //! |31 18|17 11|10 5|4 0| //! +------------------------------------------------------------+ //! ``` use super::bitfield_unit::__BindgenBitfieldUnit; #[test] fn bitfield_unit_get_bit() { let unit = __BindgenBitfieldUnit::<[u8; 2]>::new([0b10011101, 0b00011101]); let mut bits = vec![]; for i in 0..16 { bits.push(unit.get_bit(i)); } println!(); println!("bits = {:?}", bits); assert_eq!( bits, &[ // 0b10011101 true, false, true, true, true, false, false, true, // 0b00011101 true, false, true, true, true, false, false, false ] ); } #[test] fn bitfield_unit_set_bit() { let mut unit = __BindgenBitfieldUnit::<[u8; 2]>::new([0b00000000, 0b00000000]); for i in 0..16 { if i % 3 == 0 { unit.set_bit(i, true); } } for i in 0..16 { assert_eq!(unit.get_bit(i), i % 3 == 0); } let mut unit = __BindgenBitfieldUnit::<[u8; 2]>::new([0b11111111, 0b11111111]); for i in 0..16 { if i % 3 == 0 { unit.set_bit(i, false); } } for i in 0..16 { assert_eq!(unit.get_bit(i), i % 3 != 0); } } macro_rules! bitfield_unit_get { ( $( With $storage:expr , then get($start:expr, $len:expr) is $expected:expr; )* ) => { #[test] fn bitfield_unit_get() { $({ let expected = $expected; let unit = __BindgenBitfieldUnit::<_>::new($storage); let actual = unit.get($start, $len); println!(); println!("expected = {:064b}", expected); println!("actual = {:064b}", actual); assert_eq!(expected, actual); })* } } } bitfield_unit_get! { // Let's just exhaustively test getting the bits from a single byte, since // there are few enough combinations... With [0b11100010], then get(0, 1) is 0; With [0b11100010], then get(1, 1) is 1; With [0b11100010], then get(2, 1) is 0; With [0b11100010], then get(3, 1) is 0; With [0b11100010], then get(4, 1) is 0; With [0b11100010], then get(5, 1) is 1; With [0b11100010], then get(6, 1) is 1; With [0b11100010], then get(7, 1) is 1; With [0b11100010], then get(0, 2) is 0b10; With [0b11100010], then get(1, 2) is 0b01; With [0b11100010], then get(2, 2) is 0b00; With [0b11100010], then get(3, 2) is 0b00; With [0b11100010], then get(4, 2) is 0b10; With [0b11100010], then get(5, 2) is 0b11; With [0b11100010], then get(6, 2) is 0b11; With [0b11100010], then get(0, 3) is 0b010; With [0b11100010], then get(1, 3) is 0b001; With [0b11100010], then get(2, 3) is 0b000; With [0b11100010], then get(3, 3) is 0b100; With [0b11100010], then get(4, 3) is 0b110; With [0b11100010], then get(5, 3) is 0b111; With [0b11100010], then get(0, 4) is 0b0010; With [0b11100010], then get(1, 4) is 0b0001; With [0b11100010], then get(2, 4) is 0b1000; With [0b11100010], then get(3, 4) is 0b1100; With [0b11100010], then get(4, 4) is 0b1110; With [0b11100010], then get(0, 5) is 0b00010; With [0b11100010], then get(1, 5) is 0b10001; With [0b11100010], then get(2, 5) is 0b11000; With [0b11100010], then get(3, 5) is 0b11100; With [0b11100010], then get(0, 6) is 0b100010; With [0b11100010], then get(1, 6) is 0b110001; With [0b11100010], then get(2, 6) is 0b111000; With [0b11100010], then get(0, 7) is 0b1100010; With [0b11100010], then get(1, 7) is 0b1110001; With [0b11100010], then get(0, 8) is 0b11100010; // OK. Now let's test getting bits from across byte boundaries. With [0b01010101, 0b11111111, 0b00000000, 0b11111111], then get(0, 16) is 0b1111111101010101; With [0b01010101, 0b11111111, 0b00000000, 0b11111111], then get(1, 16) is 0b0111111110101010; With [0b01010101, 0b11111111, 0b00000000, 0b11111111], then get(2, 16) is 0b0011111111010101; With [0b01010101, 0b11111111, 0b00000000, 0b11111111], then get(3, 16) is 0b0001111111101010; With [0b01010101, 0b11111111, 0b00000000, 0b11111111], then get(4, 16) is 0b0000111111110101; With [0b01010101, 0b11111111, 0b00000000, 0b11111111], then get(5, 16) is 0b0000011111111010; With [0b01010101, 0b11111111, 0b00000000, 0b11111111], then get(6, 16) is 0b0000001111111101; With [0b01010101, 0b11111111, 0b00000000, 0b11111111], then get(7, 16) is 0b0000000111111110; With [0b01010101, 0b11111111, 0b00000000, 0b11111111], then get(8, 16) is 0b0000000011111111; } macro_rules! bitfield_unit_set { ( $( set($start:expr, $len:expr, $val:expr) is $expected:expr; )* ) => { #[test] fn bitfield_unit_set() { $( let mut unit = __BindgenBitfieldUnit::<[u8; 4]>::new([0, 0, 0, 0]); unit.set($start, $len, $val); let actual = unit.get(0, 32); println!(); println!("set({}, {}, {:032b}", $start, $len, $val); println!("expected = {:064b}", $expected); println!("actual = {:064b}", actual); assert_eq!($expected, actual); )* } } } bitfield_unit_set! { // Once again, let's exhaustively test single byte combinations. set(0, 1, 0b11111111) is 0b00000001; set(1, 1, 0b11111111) is 0b00000010; set(2, 1, 0b11111111) is 0b00000100; set(3, 1, 0b11111111) is 0b00001000; set(4, 1, 0b11111111) is 0b00010000; set(5, 1, 0b11111111) is 0b00100000; set(6, 1, 0b11111111) is 0b01000000; set(7, 1, 0b11111111) is 0b10000000; set(0, 2, 0b11111111) is 0b00000011; set(1, 2, 0b11111111) is 0b00000110; set(2, 2, 0b11111111) is 0b00001100; set(3, 2, 0b11111111) is 0b00011000; set(4, 2, 0b11111111) is 0b00110000; set(5, 2, 0b11111111) is 0b01100000; set(6, 2, 0b11111111) is 0b11000000; set(0, 3, 0b11111111) is 0b00000111; set(1, 3, 0b11111111) is 0b00001110; set(2, 3, 0b11111111) is 0b00011100; set(3, 3, 0b11111111) is 0b00111000; set(4, 3, 0b11111111) is 0b01110000; set(5, 3, 0b11111111) is 0b11100000; set(0, 4, 0b11111111) is 0b00001111; set(1, 4, 0b11111111) is 0b00011110; set(2, 4, 0b11111111) is 0b00111100; set(3, 4, 0b11111111) is 0b01111000; set(4, 4, 0b11111111) is 0b11110000; set(0, 5, 0b11111111) is 0b00011111; set(1, 5, 0b11111111) is 0b00111110; set(2, 5, 0b11111111) is 0b01111100; set(3, 5, 0b11111111) is 0b11111000; set(0, 6, 0b11111111) is 0b00111111; set(1, 6, 0b11111111) is 0b01111110; set(2, 6, 0b11111111) is 0b11111100; set(0, 7, 0b11111111) is 0b01111111; set(1, 7, 0b11111111) is 0b11111110; set(0, 8, 0b11111111) is 0b11111111; // And, now let's cross byte boundaries. set(0, 16, 0b1111111111111111) is 0b00000000000000001111111111111111; set(1, 16, 0b1111111111111111) is 0b00000000000000011111111111111110; set(2, 16, 0b1111111111111111) is 0b00000000000000111111111111111100; set(3, 16, 0b1111111111111111) is 0b00000000000001111111111111111000; set(4, 16, 0b1111111111111111) is 0b00000000000011111111111111110000; set(5, 16, 0b1111111111111111) is 0b00000000000111111111111111100000; set(6, 16, 0b1111111111111111) is 0b00000000001111111111111111000000; set(7, 16, 0b1111111111111111) is 0b00000000011111111111111110000000; set(8, 16, 0b1111111111111111) is 0b00000000111111111111111100000000; }