/* * (C) 1999-2011,2016,2018,2019,2020 Jack Lloyd * * Botan is released under the Simplified BSD License (see license.txt) */ #include #include #include #include #include namespace Botan { /* Sets result to a^-1 * 2^k mod a with n <= k <= 2n Returns k "The Montgomery Modular Inverse - Revisited" Çetin Koç, E. Savas https://citeseerx.ist.psu.edu/viewdoc/citations?doi=10.1.1.75.8377 A const time implementation of this algorithm is described in "Constant Time Modular Inversion" Joppe W. Bos http://www.joppebos.com/files/CTInversion.pdf */ size_t almost_montgomery_inverse(BigInt& result, const BigInt& a, const BigInt& p) { size_t k = 0; BigInt u = p, v = a, r = 0, s = 1; while(v > 0) { if(u.is_even()) { u >>= 1; s <<= 1; } else if(v.is_even()) { v >>= 1; r <<= 1; } else if(u > v) { u -= v; u >>= 1; r += s; s <<= 1; } else { v -= u; v >>= 1; s += r; r <<= 1; } ++k; } if(r >= p) { r -= p; } result = p - r; return k; } BigInt normalized_montgomery_inverse(const BigInt& a, const BigInt& p) { BigInt r; size_t k = almost_montgomery_inverse(r, a, p); for(size_t i = 0; i != k; ++i) { if(r.is_odd()) r += p; r >>= 1; } return r; } namespace { BigInt inverse_mod_odd_modulus(const BigInt& n, const BigInt& mod) { // Caller should assure these preconditions: BOTAN_DEBUG_ASSERT(n.is_positive()); BOTAN_DEBUG_ASSERT(mod.is_positive()); BOTAN_DEBUG_ASSERT(n < mod); BOTAN_DEBUG_ASSERT(mod >= 3 && mod.is_odd()); /* This uses a modular inversion algorithm designed by Niels Möller and implemented in Nettle. The same algorithm was later also adapted to GMP in mpn_sec_invert. It can be easily implemented in a way that does not depend on secret branches or memory lookups, providing resistance against some forms of side channel attack. There is also a description of the algorithm in Appendix 5 of "Fast Software Polynomial Multiplication on ARM Processors using the NEON Engine" by Danilo Câmara, Conrado P. L. Gouvêa, Julio López, and Ricardo Dahab in LNCS 8182 https://conradoplg.cryptoland.net/files/2010/12/mocrysen13.pdf Thanks to Niels for creating the algorithm, explaining some things about it, and the reference to the paper. */ const size_t mod_words = mod.sig_words(); BOTAN_ASSERT(mod_words > 0, "Not empty"); secure_vector tmp_mem(5*mod_words); word* v_w = &tmp_mem[0]; word* u_w = &tmp_mem[1*mod_words]; word* b_w = &tmp_mem[2*mod_words]; word* a_w = &tmp_mem[3*mod_words]; word* mp1o2 = &tmp_mem[4*mod_words]; CT::poison(tmp_mem.data(), tmp_mem.size()); copy_mem(a_w, n.data(), std::min(n.size(), mod_words)); copy_mem(b_w, mod.data(), std::min(mod.size(), mod_words)); u_w[0] = 1; // v_w = 0 // compute (mod + 1) / 2 which [because mod is odd] is equal to // (mod / 2) + 1 copy_mem(mp1o2, mod.data(), std::min(mod.size(), mod_words)); bigint_shr1(mp1o2, mod_words, 0, 1); word carry = bigint_add2_nc(mp1o2, mod_words, u_w, 1); BOTAN_ASSERT_NOMSG(carry == 0); // Only n.bits() + mod.bits() iterations are required, but avoid leaking the size of n const size_t execs = 2 * mod.bits(); for(size_t i = 0; i != execs; ++i) { const word odd_a = a_w[0] & 1; //if(odd_a) a -= b word underflow = bigint_cnd_sub(odd_a, a_w, b_w, mod_words); //if(underflow) { b -= a; a = abs(a); swap(u, v); } bigint_cnd_add(underflow, b_w, a_w, mod_words); bigint_cnd_abs(underflow, a_w, mod_words); bigint_cnd_swap(underflow, u_w, v_w, mod_words); // a >>= 1 bigint_shr1(a_w, mod_words, 0, 1); //if(odd_a) u -= v; word borrow = bigint_cnd_sub(odd_a, u_w, v_w, mod_words); // if(borrow) u += p bigint_cnd_add(borrow, u_w, mod.data(), mod_words); const word odd_u = u_w[0] & 1; // u >>= 1 bigint_shr1(u_w, mod_words, 0, 1); //if(odd_u) u += mp1o2; bigint_cnd_add(odd_u, u_w, mp1o2, mod_words); } auto a_is_0 = CT::Mask::set(); for(size_t i = 0; i != mod_words; ++i) a_is_0 &= CT::Mask::is_zero(a_w[i]); auto b_is_1 = CT::Mask::is_equal(b_w[0], 1); for(size_t i = 1; i != mod_words; ++i) b_is_1 &= CT::Mask::is_zero(b_w[i]); BOTAN_ASSERT(a_is_0.is_set(), "A is zero"); // if b != 1 then gcd(n,mod) > 1 and inverse does not exist // in which case zero out the result to indicate this (~b_is_1).if_set_zero_out(v_w, mod_words); /* * We've placed the result in the lowest words of the temp buffer. * So just clear out the other values and then give that buffer to a * BigInt. */ clear_mem(&tmp_mem[mod_words], 4*mod_words); CT::unpoison(tmp_mem.data(), tmp_mem.size()); BigInt r; r.swap_reg(tmp_mem); return r; } BigInt inverse_mod_pow2(const BigInt& a1, size_t k) { /* * From "A New Algorithm for Inversion mod p^k" by Çetin Kaya Koç * https://eprint.iacr.org/2017/411.pdf sections 5 and 7. */ if(a1.is_even()) return 0; BigInt a = a1; a.mask_bits(k); BigInt b = 1; BigInt X = 0; BigInt newb; const size_t a_words = a.sig_words(); X.grow_to(round_up(k, BOTAN_MP_WORD_BITS) / BOTAN_MP_WORD_BITS); b.grow_to(a_words); /* Hide the exact value of k. k is anyway known to word length granularity because of the length of a, so no point in doing more than this. */ const size_t iter = round_up(k, BOTAN_MP_WORD_BITS); for(size_t i = 0; i != iter; ++i) { const bool b0 = b.get_bit(0); X.conditionally_set_bit(i, b0); newb = b - a; b.ct_cond_assign(b0, newb); b >>= 1; } X.mask_bits(k); X.const_time_unpoison(); return X; } } BigInt inverse_mod(const BigInt& n, const BigInt& mod) { if(mod.is_zero()) throw BigInt::DivideByZero(); if(mod.is_negative() || n.is_negative()) throw Invalid_Argument("inverse_mod: arguments must be non-negative"); if(n.is_zero() || (n.is_even() && mod.is_even())) return 0; if(mod.is_odd()) { /* Fastpath for common case. This leaks information if n > mod but we don't guarantee const time behavior in that case. */ if(n < mod) return inverse_mod_odd_modulus(n, mod); else return inverse_mod_odd_modulus(ct_modulo(n, mod), mod); } const size_t mod_lz = low_zero_bits(mod); BOTAN_ASSERT_NOMSG(mod_lz > 0); const size_t mod_bits = mod.bits(); BOTAN_ASSERT_NOMSG(mod_bits > mod_lz); if(mod_lz == mod_bits - 1) { // In this case we are performing an inversion modulo 2^k return inverse_mod_pow2(n, mod_lz); } /* * In this case we are performing an inversion modulo 2^k*o for * some k > 1 and some odd (not necessarily prime) integer. * Compute the inversions modulo 2^k and modulo o, then combine them * using CRT, which is possible because 2^k and o are relatively prime. */ const BigInt o = mod >> mod_lz; const BigInt n_redc = ct_modulo(n, o); const BigInt inv_o = inverse_mod_odd_modulus(n_redc, o); const BigInt inv_2k = inverse_mod_pow2(n, mod_lz); // No modular inverse in this case: if(inv_o == 0 || inv_2k == 0) return 0; const BigInt m2k = BigInt::power_of_2(mod_lz); // Compute the CRT parameter const BigInt c = inverse_mod_pow2(o, mod_lz); // Compute h = c*(inv_2k-inv_o) mod 2^k BigInt h = c * (inv_2k - inv_o); const bool h_neg = h.is_negative(); h.set_sign(BigInt::Positive); h.mask_bits(mod_lz); const bool h_nonzero = h.is_nonzero(); h.ct_cond_assign(h_nonzero && h_neg, m2k - h); // Return result inv_o + h * o h *= o; h += inv_o; return h; } // Deprecated forwarding functions: BigInt inverse_euclid(const BigInt& x, const BigInt& modulus) { return inverse_mod(x, modulus); } BigInt ct_inverse_mod_odd_modulus(const BigInt& n, const BigInt& mod) { return inverse_mod_odd_modulus(n, mod); } word monty_inverse(word a) { if(a % 2 == 0) throw Invalid_Argument("monty_inverse only valid for odd integers"); /* * From "A New Algorithm for Inversion mod p^k" by Çetin Kaya Koç * https://eprint.iacr.org/2017/411.pdf sections 5 and 7. */ word b = 1; word r = 0; for(size_t i = 0; i != BOTAN_MP_WORD_BITS; ++i) { const word bi = b % 2; r >>= 1; r += bi << (BOTAN_MP_WORD_BITS - 1); b -= a * bi; b >>= 1; } // Now invert in addition space r = (MP_WORD_MAX - r) + 1; return r; } }