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# arrays referenced using @ subscript and positional parameters should behave
# the same way
foo=(0 0 0); [[ -z ${foo[@]#0} ]]; echo $?
recho "${foo[@]#0}"
bar=${foo[@]#0}
recho bar
recho $bar
recho -$bar-
recho "$bar"
qux="${foo[@]#0}"
recho qux
recho $qux
recho -$qux-
recho "$qux"
unset foo qux bar
set -- 0 0 0
recho "${@#0}"
bar=${@#0}
recho bar
recho $bar
recho -$bar-
recho "$bar"
qux="${@#0}"
recho qux
recho $qux
recho -$qux-
recho "$qux"
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