Adding upstream version 4.19.249.upstream/4.19.249upstream

Signed-off-by: Daniel Baumann <daniel.baumann@progress-linux.org>

3 files changed, 72 insertions, 0 deletions

diff --git a/scripts/kconfig/tests/auto_submenu/Kconfig b/scripts/kconfig/tests/auto_submenu/Kconfig
new file mode 100644
index 000000000..c17bf2caa
--- /dev/null
+++ b/scripts/kconfig/tests/auto_submenu/Kconfig
@@ -0,0 +1,50 @@
+config A
+	bool "A"
+	default y
+
+config A0
+	bool "A0"
+	depends on A
+	default y
+	help
+	  This depends on A, so should be a submenu of A.
+
+config A0_0
+	bool "A1_0"
+	depends on A0
+	help
+	  Submenus are created recursively.
+	  This should be a submenu of A0.
+
+config A1
+	bool "A1"
+	depends on A
+	default y
+	help
+	  This should line up with A0.
+
+choice
+	prompt "choice"
+	depends on A1
+	help
+	  Choice should become a submenu as well.
+
+config A1_0
+	bool "A1_0"
+
+config A1_1
+	bool "A1_1"
+
+endchoice
+
+config B
+	bool "B"
+	help
+	  This is independent of A.
+
+config C
+	bool "C"
+	depends on A
+	help
+	  This depends on A, but not a consecutive item, so can/should not
+	  be a submenu.
diff --git a/scripts/kconfig/tests/auto_submenu/__init__.py b/scripts/kconfig/tests/auto_submenu/__init__.py
new file mode 100644
index 000000000..32e79b85f
--- /dev/null
+++ b/scripts/kconfig/tests/auto_submenu/__init__.py
@@ -0,0 +1,12 @@
+"""
+Create submenu for symbols that depend on the preceding one.
+
+If a symbols has dependency on the preceding symbol, the menu entry
+should become the submenu of the preceding one, and displayed with
+deeper indentation.
+"""
+
+
+def test(conf):
+    assert conf.oldaskconfig() == 0
+    assert conf.stdout_contains('expected_stdout')
diff --git a/scripts/kconfig/tests/auto_submenu/expected_stdout b/scripts/kconfig/tests/auto_submenu/expected_stdout
new file mode 100644
index 000000000..bf5236f39
--- /dev/null
+++ b/scripts/kconfig/tests/auto_submenu/expected_stdout
@@ -0,0 +1,10 @@
+A (A) [Y/n/?] (NEW) 
+  A0 (A0) [Y/n/?] (NEW) 
+    A1_0 (A0_0) [N/y/?] (NEW) 
+  A1 (A1) [Y/n/?] (NEW) 
+    choice
+    > 1. A1_0 (A1_0) (NEW)
+      2. A1_1 (A1_1) (NEW)
+    choice[1-2?]: 
+B (B) [N/y/?] (NEW) 
+C (C) [N/y/?] (NEW)