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# Tests that '@' is recognized as an Operator
---input---
S = (H @ beta - r).T @ inv(H @ V @ H.T) @ (H @ beta - r)
---tokens---
'S' Name
' ' Text
'=' Operator
' ' Text
'(' Punctuation
'H' Name
' ' Text
'@' Operator
' ' Text
'beta' Name
' ' Text
'-' Operator
' ' Text
'r' Name
')' Punctuation
'.' Operator
'T' Name
' ' Text
'@' Operator
' ' Text
'inv' Name
'(' Punctuation
'H' Name
' ' Text
'@' Operator
' ' Text
'V' Name
' ' Text
'@' Operator
' ' Text
'H' Name
'.' Operator
'T' Name
')' Punctuation
' ' Text
'@' Operator
' ' Text
'(' Punctuation
'H' Name
' ' Text
'@' Operator
' ' Text
'beta' Name
' ' Text
'-' Operator
' ' Text
'r' Name
')' Punctuation
'\n' Text.Whitespace
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