Adding upstream version 124.0.1.upstream/124.0.1

Signed-off-by: Daniel Baumann <daniel.baumann@progress-linux.org>

1 files changed, 509 insertions, 0 deletions

diff --git a/gfx/cairo/libpixman/src/pixman-radial-gradient.c b/gfx/cairo/libpixman/src/pixman-radial-gradient.c
new file mode 100644
index 0000000000..e8e99c98b9
--- /dev/null
+++ b/gfx/cairo/libpixman/src/pixman-radial-gradient.c
@@ -0,0 +1,509 @@
+/* -*- Mode: c; c-basic-offset: 4; tab-width: 8; indent-tabs-mode: t; -*- */
+/*
+ *
+ * Copyright © 2000 Keith Packard, member of The XFree86 Project, Inc.
+ * Copyright © 2000 SuSE, Inc.
+ *             2005 Lars Knoll & Zack Rusin, Trolltech
+ * Copyright © 2007 Red Hat, Inc.
+ *
+ *
+ * Permission to use, copy, modify, distribute, and sell this software and its
+ * documentation for any purpose is hereby granted without fee, provided that
+ * the above copyright notice appear in all copies and that both that
+ * copyright notice and this permission notice appear in supporting
+ * documentation, and that the name of Keith Packard not be used in
+ * advertising or publicity pertaining to distribution of the software without
+ * specific, written prior permission.  Keith Packard makes no
+ * representations about the suitability of this software for any purpose.  It
+ * is provided "as is" without express or implied warranty.
+ *
+ * THE COPYRIGHT HOLDERS DISCLAIM ALL WARRANTIES WITH REGARD TO THIS
+ * SOFTWARE, INCLUDING ALL IMPLIED WARRANTIES OF MERCHANTABILITY AND
+ * FITNESS, IN NO EVENT SHALL THE COPYRIGHT HOLDERS BE LIABLE FOR ANY
+ * SPECIAL, INDIRECT OR CONSEQUENTIAL DAMAGES OR ANY DAMAGES
+ * WHATSOEVER RESULTING FROM LOSS OF USE, DATA OR PROFITS, WHETHER IN
+ * AN ACTION OF CONTRACT, NEGLIGENCE OR OTHER TORTIOUS ACTION, ARISING
+ * OUT OF OR IN CONNECTION WITH THE USE OR PERFORMANCE OF THIS
+ * SOFTWARE.
+ */
+
+#ifdef HAVE_CONFIG_H
+#include <config.h>
+#endif
+#include <stdlib.h>
+#include <math.h>
+#include "pixman-private.h"
+
+static inline pixman_fixed_32_32_t
+dot (pixman_fixed_48_16_t x1,
+     pixman_fixed_48_16_t y1,
+     pixman_fixed_48_16_t z1,
+     pixman_fixed_48_16_t x2,
+     pixman_fixed_48_16_t y2,
+     pixman_fixed_48_16_t z2)
+{
+    /*
+     * Exact computation, assuming that the input values can
+     * be represented as pixman_fixed_16_16_t
+     */
+    return x1 * x2 + y1 * y2 + z1 * z2;
+}
+
+static inline double
+fdot (double x1,
+      double y1,
+      double z1,
+      double x2,
+      double y2,
+      double z2)
+{
+    /*
+     * Error can be unbound in some special cases.
+     * Using clever dot product algorithms (for example compensated
+     * dot product) would improve this but make the code much less
+     * obvious
+     */
+    return x1 * x2 + y1 * y2 + z1 * z2;
+}
+
+static void
+radial_write_color (double                         a,
+		    double                         b,
+		    double                         c,
+		    double                         inva,
+		    double                         dr,
+		    double                         mindr,
+		    pixman_gradient_walker_t      *walker,
+		    pixman_repeat_t                repeat,
+		    int                            Bpp,
+		    pixman_gradient_walker_write_t write_pixel,
+		    uint32_t                      *buffer)
+{
+    /*
+     * In this function error propagation can lead to bad results:
+     *  - discr can have an unbound error (if b*b-a*c is very small),
+     *    potentially making it the opposite sign of what it should have been
+     *    (thus clearing a pixel that would have been colored or vice-versa)
+     *    or propagating the error to sqrtdiscr;
+     *    if discr has the wrong sign or b is very small, this can lead to bad
+     *    results
+     *
+     *  - the algorithm used to compute the solutions of the quadratic
+     *    equation is not numerically stable (but saves one division compared
+     *    to the numerically stable one);
+     *    this can be a problem if a*c is much smaller than b*b
+     *
+     *  - the above problems are worse if a is small (as inva becomes bigger)
+     */
+    double discr;
+
+    if (a == 0)
+    {
+	double t;
+
+	if (b == 0)
+	{
+	    memset (buffer, 0, Bpp);
+	    return;
+	}
+
+	t = pixman_fixed_1 / 2 * c / b;
+	if (repeat == PIXMAN_REPEAT_NONE)
+	{
+	    if (0 <= t && t <= pixman_fixed_1)
+	    {
+		write_pixel (walker, t, buffer);
+		return;
+	    }
+	}
+	else
+	{
+	    if (t * dr >= mindr)
+	    {
+		write_pixel (walker, t, buffer);
+		return;
+	    }
+	}
+
+	memset (buffer, 0, Bpp);
+	return;
+    }
+
+    discr = fdot (b, a, 0, b, -c, 0);
+    if (discr >= 0)
+    {
+	double sqrtdiscr, t0, t1;
+
+	sqrtdiscr = sqrt (discr);
+	t0 = (b + sqrtdiscr) * inva;
+	t1 = (b - sqrtdiscr) * inva;
+
+	/*
+	 * The root that must be used is the biggest one that belongs
+	 * to the valid range ([0,1] for PIXMAN_REPEAT_NONE, any
+	 * solution that results in a positive radius otherwise).
+	 *
+	 * If a > 0, t0 is the biggest solution, so if it is valid, it
+	 * is the correct result.
+	 *
+	 * If a < 0, only one of the solutions can be valid, so the
+	 * order in which they are tested is not important.
+	 */
+	if (repeat == PIXMAN_REPEAT_NONE)
+	{
+	    if (0 <= t0 && t0 <= pixman_fixed_1)
+	    {
+		write_pixel (walker, t0, buffer);
+		return;
+	    }
+	    else if (0 <= t1 && t1 <= pixman_fixed_1)
+	    {
+		write_pixel (walker, t1, buffer);
+		return;
+           }
+	}
+	else
+	{
+	    if (t0 * dr >= mindr)
+	    {
+		write_pixel (walker, t0, buffer);
+		return;
+	    }
+	    else if (t1 * dr >= mindr)
+	    {
+		write_pixel (walker, t1, buffer);
+		return;
+	    }
+	}
+    }
+
+    memset (buffer, 0, Bpp);
+    return;
+}
+
+static uint32_t *
+radial_get_scanline (pixman_iter_t                 *iter,
+		     const uint32_t                *mask,
+		     int                            Bpp,
+		     pixman_gradient_walker_write_t write_pixel)
+{
+    /*
+     * Implementation of radial gradients following the PDF specification.
+     * See section 8.7.4.5.4 Type 3 (Radial) Shadings of the PDF Reference
+     * Manual (PDF 32000-1:2008 at the time of this writing).
+     *
+     * In the radial gradient problem we are given two circles (c₁,r₁) and
+     * (c₂,r₂) that define the gradient itself.
+     *
+     * Mathematically the gradient can be defined as the family of circles
+     *
+     *     ((1-t)·c₁ + t·(c₂), (1-t)·r₁ + t·r₂)
+     *
+     * excluding those circles whose radius would be < 0. When a point
+     * belongs to more than one circle, the one with a bigger t is the only
+     * one that contributes to its color. When a point does not belong
+     * to any of the circles, it is transparent black, i.e. RGBA (0, 0, 0, 0).
+     * Further limitations on the range of values for t are imposed when
+     * the gradient is not repeated, namely t must belong to [0,1].
+     *
+     * The graphical result is the same as drawing the valid (radius > 0)
+     * circles with increasing t in [-inf, +inf] (or in [0,1] if the gradient
+     * is not repeated) using SOURCE operator composition.
+     *
+     * It looks like a cone pointing towards the viewer if the ending circle
+     * is smaller than the starting one, a cone pointing inside the page if
+     * the starting circle is the smaller one and like a cylinder if they
+     * have the same radius.
+     *
+     * What we actually do is, given the point whose color we are interested
+     * in, compute the t values for that point, solving for t in:
+     *
+     *     length((1-t)·c₁ + t·(c₂) - p) = (1-t)·r₁ + t·r₂
+     *
+     * Let's rewrite it in a simpler way, by defining some auxiliary
+     * variables:
+     *
+     *     cd = c₂ - c₁
+     *     pd = p - c₁
+     *     dr = r₂ - r₁
+     *     length(t·cd - pd) = r₁ + t·dr
+     *
+     * which actually means
+     *
+     *     hypot(t·cdx - pdx, t·cdy - pdy) = r₁ + t·dr
+     *
+     * or
+     *
+     *     ⎷((t·cdx - pdx)² + (t·cdy - pdy)²) = r₁ + t·dr.
+     *
+     * If we impose (as stated earlier) that r₁ + t·dr >= 0, it becomes:
+     *
+     *     (t·cdx - pdx)² + (t·cdy - pdy)² = (r₁ + t·dr)²
+     *
+     * where we can actually expand the squares and solve for t:
+     *
+     *     t²cdx² - 2t·cdx·pdx + pdx² + t²cdy² - 2t·cdy·pdy + pdy² =
+     *       = r₁² + 2·r₁·t·dr + t²·dr²
+     *
+     *     (cdx² + cdy² - dr²)t² - 2(cdx·pdx + cdy·pdy + r₁·dr)t +
+     *         (pdx² + pdy² - r₁²) = 0
+     *
+     *     A = cdx² + cdy² - dr²
+     *     B = pdx·cdx + pdy·cdy + r₁·dr
+     *     C = pdx² + pdy² - r₁²
+     *     At² - 2Bt + C = 0
+     *
+     * The solutions (unless the equation degenerates because of A = 0) are:
+     *
+     *     t = (B ± ⎷(B² - A·C)) / A
+     *
+     * The solution we are going to prefer is the bigger one, unless the
+     * radius associated to it is negative (or it falls outside the valid t
+     * range).
+     *
+     * Additional observations (useful for optimizations):
+     * A does not depend on p
+     *
+     * A < 0 <=> one of the two circles completely contains the other one
+     *   <=> for every p, the radiuses associated with the two t solutions
+     *       have opposite sign
+     */
+    pixman_image_t *image = iter->image;
+    int x = iter->x;
+    int y = iter->y;
+    int width = iter->width;
+    uint32_t *buffer = iter->buffer;
+
+    gradient_t *gradient = (gradient_t *)image;
+    radial_gradient_t *radial = (radial_gradient_t *)image;
+    uint32_t *end = buffer + width * (Bpp / 4);
+    pixman_gradient_walker_t walker;
+    pixman_vector_t v, unit;
+
+    /* reference point is the center of the pixel */
+    v.vector[0] = pixman_int_to_fixed (x) + pixman_fixed_1 / 2;
+    v.vector[1] = pixman_int_to_fixed (y) + pixman_fixed_1 / 2;
+    v.vector[2] = pixman_fixed_1;
+
+    _pixman_gradient_walker_init (&walker, gradient, image->common.repeat);
+
+    if (image->common.transform)
+    {
+	if (!pixman_transform_point_3d (image->common.transform, &v))
+	    return iter->buffer;
+
+	unit.vector[0] = image->common.transform->matrix[0][0];
+	unit.vector[1] = image->common.transform->matrix[1][0];
+	unit.vector[2] = image->common.transform->matrix[2][0];
+    }
+    else
+    {
+	unit.vector[0] = pixman_fixed_1;
+	unit.vector[1] = 0;
+	unit.vector[2] = 0;
+    }
+
+    if (unit.vector[2] == 0 && v.vector[2] == pixman_fixed_1)
+    {
+	/*
+	 * Given:
+	 *
+	 * t = (B ± ⎷(B² - A·C)) / A
+	 *
+	 * where
+	 *
+	 * A = cdx² + cdy² - dr²
+	 * B = pdx·cdx + pdy·cdy + r₁·dr
+	 * C = pdx² + pdy² - r₁²
+	 * det = B² - A·C
+	 *
+	 * Since we have an affine transformation, we know that (pdx, pdy)
+	 * increase linearly with each pixel,
+	 *
+	 * pdx = pdx₀ + n·ux,
+	 * pdy = pdy₀ + n·uy,
+	 *
+	 * we can then express B, C and det through multiple differentiation.
+	 */
+	pixman_fixed_32_32_t b, db, c, dc, ddc;
+
+	/* warning: this computation may overflow */
+	v.vector[0] -= radial->c1.x;
+	v.vector[1] -= radial->c1.y;
+
+	/*
+	 * B and C are computed and updated exactly.
+	 * If fdot was used instead of dot, in the worst case it would
+	 * lose 11 bits of precision in each of the multiplication and
+	 * summing up would zero out all the bit that were preserved,
+	 * thus making the result 0 instead of the correct one.
+	 * This would mean a worst case of unbound relative error or
+	 * about 2^10 absolute error
+	 */
+	b = dot (v.vector[0], v.vector[1], radial->c1.radius,
+		 radial->delta.x, radial->delta.y, radial->delta.radius);
+	db = dot (unit.vector[0], unit.vector[1], 0,
+		  radial->delta.x, radial->delta.y, 0);
+
+	c = dot (v.vector[0], v.vector[1],
+		 -((pixman_fixed_48_16_t) radial->c1.radius),
+		 v.vector[0], v.vector[1], radial->c1.radius);
+	dc = dot (2 * (pixman_fixed_48_16_t) v.vector[0] + unit.vector[0],
+		  2 * (pixman_fixed_48_16_t) v.vector[1] + unit.vector[1],
+		  0,
+		  unit.vector[0], unit.vector[1], 0);
+	ddc = 2 * dot (unit.vector[0], unit.vector[1], 0,
+		       unit.vector[0], unit.vector[1], 0);
+
+	while (buffer < end)
+	{
+	    if (!mask || *mask++)
+	    {
+		radial_write_color (radial->a, b, c,
+				    radial->inva,
+				    radial->delta.radius,
+				    radial->mindr,
+				    &walker,
+				    image->common.repeat,
+				    Bpp,
+				    write_pixel,
+				    buffer);
+	    }
+
+	    b += db;
+	    c += dc;
+	    dc += ddc;
+	    buffer += (Bpp / 4);
+	}
+    }
+    else
+    {
+	/* projective */
+	/* Warning:
+	 * error propagation guarantees are much looser than in the affine case
+	 */
+	while (buffer < end)
+	{
+	    if (!mask || *mask++)
+	    {
+		if (v.vector[2] != 0)
+		{
+		    double pdx, pdy, invv2, b, c;
+
+		    invv2 = 1. * pixman_fixed_1 / v.vector[2];
+
+		    pdx = v.vector[0] * invv2 - radial->c1.x;
+		    /*    / pixman_fixed_1 */
+
+		    pdy = v.vector[1] * invv2 - radial->c1.y;
+		    /*    / pixman_fixed_1 */
+
+		    b = fdot (pdx, pdy, radial->c1.radius,
+			      radial->delta.x, radial->delta.y,
+			      radial->delta.radius);
+		    /*  / pixman_fixed_1 / pixman_fixed_1 */
+
+		    c = fdot (pdx, pdy, -radial->c1.radius,
+			      pdx, pdy, radial->c1.radius);
+		    /*  / pixman_fixed_1 / pixman_fixed_1 */
+
+		    radial_write_color (radial->a, b, c,
+					radial->inva,
+					radial->delta.radius,
+					radial->mindr,
+					&walker,
+					image->common.repeat,
+					Bpp,
+					write_pixel,
+					buffer);
+		}
+		else
+		{
+		    memset (buffer, 0, Bpp);
+		}
+	    }
+
+	    buffer += (Bpp / 4);
+
+	    v.vector[0] += unit.vector[0];
+	    v.vector[1] += unit.vector[1];
+	    v.vector[2] += unit.vector[2];
+	}
+    }
+
+    iter->y++;
+    return iter->buffer;
+}
+
+static uint32_t *
+radial_get_scanline_narrow (pixman_iter_t *iter, const uint32_t *mask)
+{
+    return radial_get_scanline (iter, mask, 4,
+				_pixman_gradient_walker_write_narrow);
+}
+
+static uint32_t *
+radial_get_scanline_wide (pixman_iter_t *iter, const uint32_t *mask)
+{
+    return radial_get_scanline (iter, NULL, 16,
+				_pixman_gradient_walker_write_wide);
+}
+
+void
+_pixman_radial_gradient_iter_init (pixman_image_t *image, pixman_iter_t *iter)
+{
+    if (iter->iter_flags & ITER_NARROW)
+	iter->get_scanline = radial_get_scanline_narrow;
+    else
+	iter->get_scanline = radial_get_scanline_wide;
+}
+
+PIXMAN_EXPORT pixman_image_t *
+pixman_image_create_radial_gradient (const pixman_point_fixed_t *  inner,
+				     const pixman_point_fixed_t *  outer,
+				     pixman_fixed_t                inner_radius,
+				     pixman_fixed_t                outer_radius,
+				     const pixman_gradient_stop_t *stops,
+				     int                           n_stops)
+{
+    pixman_image_t *image;
+    radial_gradient_t *radial;
+
+    image = _pixman_image_allocate ();
+
+    if (!image)
+	return NULL;
+
+    radial = &image->radial;
+
+    if (!_pixman_init_gradient (&radial->common, stops, n_stops))
+    {
+	free (image);
+	return NULL;
+    }
+
+    image->type = RADIAL;
+
+    radial->c1.x = inner->x;
+    radial->c1.y = inner->y;
+    radial->c1.radius = inner_radius;
+    radial->c2.x = outer->x;
+    radial->c2.y = outer->y;
+    radial->c2.radius = outer_radius;
+
+    /* warning: this computations may overflow */
+    radial->delta.x = radial->c2.x - radial->c1.x;
+    radial->delta.y = radial->c2.y - radial->c1.y;
+    radial->delta.radius = radial->c2.radius - radial->c1.radius;
+
+    /* computed exactly, then cast to double -> every bit of the double
+       representation is correct (53 bits) */
+    radial->a = dot (radial->delta.x, radial->delta.y, -radial->delta.radius,
+		     radial->delta.x, radial->delta.y, radial->delta.radius);
+    if (radial->a != 0)
+	radial->inva = 1. * pixman_fixed_1 / radial->a;
+
+    radial->mindr = -1. * pixman_fixed_1 * radial->c1.radius;
+
+    return image;
+}