diff options
Diffstat (limited to 'security/nss/lib/freebl/mpi/doc/mul.txt')
-rw-r--r-- | security/nss/lib/freebl/mpi/doc/mul.txt | 77 |
1 files changed, 77 insertions, 0 deletions
diff --git a/security/nss/lib/freebl/mpi/doc/mul.txt b/security/nss/lib/freebl/mpi/doc/mul.txt new file mode 100644 index 0000000000..975f56ddbe --- /dev/null +++ b/security/nss/lib/freebl/mpi/doc/mul.txt @@ -0,0 +1,77 @@ +Multiplication + +This describes the multiplication algorithm used by the MPI library. + +This is basically a standard "schoolbook" algorithm. It is slow -- +O(mn) for m = #a, n = #b -- but easy to implement and verify. +Basically, we run two nested loops, as illustrated here (R is the +radix): + +k = 0 +for j <- 0 to (#b - 1) + for i <- 0 to (#a - 1) + w = (a[j] * b[i]) + k + c[i+j] + c[i+j] = w mod R + k = w div R + endfor + c[i+j] = k; + k = 0; +endfor + +It is necessary that 'w' have room for at least two radix R digits. +The product of any two digits in radix R is at most: + + (R - 1)(R - 1) = R^2 - 2R + 1 + +Since a two-digit radix-R number can hold R^2 - 1 distinct values, +this insures that the product will fit into the two-digit register. + +To insure that two digits is enough for w, we must also show that +there is room for the carry-in from the previous multiplication, and +the current value of the product digit that is being recomputed. +Assuming each of these may be as big as R - 1 (and no larger, +certainly), two digits will be enough if and only if: + + (R^2 - 2R + 1) + 2(R - 1) <= R^2 - 1 + +Solving this equation shows that, indeed, this is the case: + + R^2 - 2R + 1 + 2R - 2 <= R^2 - 1 + + R^2 - 1 <= R^2 - 1 + +This suggests that a good radix would be one more than the largest +value that can be held in half a machine word -- so, for example, as +in this implementation, where we used a radix of 65536 on a machine +with 4-byte words. Another advantage of a radix of this sort is that +binary-level operations are easy on numbers in this representation. + +Here's an example multiplication worked out longhand in radix-10, +using the above algorithm: + + a = 999 + b = x 999 + ------------- + p = 98001 + +w = (a[jx] * b[ix]) + kin + c[ix + jx] +c[ix+jx] = w % RADIX +k = w / RADIX + product +ix jx a[jx] b[ix] kin w c[i+j] kout 000000 +0 0 9 9 0 81+0+0 1 8 000001 +0 1 9 9 8 81+8+0 9 8 000091 +0 2 9 9 8 81+8+0 9 8 000991 + 8 0 008991 +1 0 9 9 0 81+0+9 0 9 008901 +1 1 9 9 9 81+9+9 9 9 008901 +1 2 9 9 9 81+9+8 8 9 008901 + 9 0 098901 +2 0 9 9 0 81+0+9 0 9 098001 +2 1 9 9 9 81+9+8 8 9 098001 +2 2 9 9 9 81+9+9 9 9 098001 + +------------------------------------------------------------------ + This Source Code Form is subject to the terms of the Mozilla Public + # License, v. 2.0. If a copy of the MPL was not distributed with this + # file, You can obtain one at http://mozilla.org/MPL/2.0/. |