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authorDaniel Baumann <daniel.baumann@progress-linux.org>2024-04-17 12:19:13 +0000
committerDaniel Baumann <daniel.baumann@progress-linux.org>2024-04-17 12:19:13 +0000
commit218caa410aa38c29984be31a5229b9fa717560ee (patch)
treec54bd55eeb6e4c508940a30e94c0032fbd45d677 /tests/ui/specialization/specialization-default-types.rs
parentReleasing progress-linux version 1.67.1+dfsg1-1~progress7.99u1. (diff)
downloadrustc-218caa410aa38c29984be31a5229b9fa717560ee.tar.xz
rustc-218caa410aa38c29984be31a5229b9fa717560ee.zip
Merging upstream version 1.68.2+dfsg1.
Signed-off-by: Daniel Baumann <daniel.baumann@progress-linux.org>
Diffstat (limited to 'tests/ui/specialization/specialization-default-types.rs')
-rw-r--r--tests/ui/specialization/specialization-default-types.rs35
1 files changed, 35 insertions, 0 deletions
diff --git a/tests/ui/specialization/specialization-default-types.rs b/tests/ui/specialization/specialization-default-types.rs
new file mode 100644
index 000000000..346471f11
--- /dev/null
+++ b/tests/ui/specialization/specialization-default-types.rs
@@ -0,0 +1,35 @@
+// It should not be possible to use the concrete value of a defaulted
+// associated type in the impl defining it -- otherwise, what happens
+// if it's overridden?
+
+#![feature(specialization)] //~ WARN the feature `specialization` is incomplete
+
+trait Example {
+ type Output;
+ fn generate(self) -> Self::Output;
+}
+
+impl<T> Example for T {
+ default type Output = Box<T>;
+ default fn generate(self) -> Self::Output {
+ Box::new(self) //~ ERROR mismatched types
+ }
+}
+
+impl Example for bool {
+ type Output = bool;
+ fn generate(self) -> bool { self }
+}
+
+fn trouble<T>(t: T) -> Box<T> {
+ Example::generate(t) //~ ERROR mismatched types
+}
+
+fn weaponize() -> bool {
+ let b: Box<bool> = trouble(true);
+ *b
+}
+
+fn main() {
+ weaponize();
+}