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The compiler doesn't know what method to call because more than one method
has the same prototype.
Erroneous code example:
```compile_fail,E0034
struct Test;
trait Trait1 {
fn foo();
}
trait Trait2 {
fn foo();
}
impl Trait1 for Test { fn foo() {} }
impl Trait2 for Test { fn foo() {} }
fn main() {
Test::foo() // error, which foo() to call?
}
```
To avoid this error, you have to keep only one of them and remove the others.
So let's take our example and fix it:
```
struct Test;
trait Trait1 {
fn foo();
}
impl Trait1 for Test { fn foo() {} }
fn main() {
Test::foo() // and now that's good!
}
```
However, a better solution would be using fully explicit naming of type and
trait:
```
struct Test;
trait Trait1 {
fn foo();
}
trait Trait2 {
fn foo();
}
impl Trait1 for Test { fn foo() {} }
impl Trait2 for Test { fn foo() {} }
fn main() {
<Test as Trait1>::foo()
}
```
One last example:
```
trait F {
fn m(&self);
}
trait G {
fn m(&self);
}
struct X;
impl F for X { fn m(&self) { println!("I am F"); } }
impl G for X { fn m(&self) { println!("I am G"); } }
fn main() {
let f = X;
F::m(&f); // it displays "I am F"
G::m(&f); // it displays "I am G"
}
```
|
