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An `if` expression is missing an `else` block.
Erroneous code example:
```compile_fail,E0317
let x = 5;
let a = if x == 5 {
1
};
```
This error occurs when an `if` expression without an `else` block is used in a
context where a type other than `()` is expected. In the previous code example,
the `let` expression was expecting a value but since there was no `else`, no
value was returned.
An `if` expression without an `else` block has the type `()`, so this is a type
error. To resolve it, add an `else` block having the same type as the `if`
block.
So to fix the previous code example:
```
let x = 5;
let a = if x == 5 {
1
} else {
2
};
```
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