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#![warn(clippy::extend_with_drain)]
#![allow(clippy::iter_with_drain)]
use std::collections::BinaryHeap;
fn main() {
//gets linted
let mut vec1 = vec![0u8; 1024];
let mut vec2: std::vec::Vec<u8> = Vec::new();
vec2.append(&mut vec1);
let mut vec3 = vec![0u8; 1024];
let mut vec4: std::vec::Vec<u8> = Vec::new();
vec4.append(&mut vec3);
let mut vec11: std::vec::Vec<u8> = Vec::new();
vec11.append(&mut return_vector());
//won't get linted it doesn't move the entire content of a vec into another
let mut test1 = vec![0u8, 10];
let mut test2: std::vec::Vec<u8> = Vec::new();
test2.extend(test1.drain(4..10));
let mut vec3 = vec![0u8; 104];
let mut vec7: std::vec::Vec<u8> = Vec::new();
vec3.append(&mut vec7);
let mut vec5 = vec![0u8; 1024];
let mut vec6: std::vec::Vec<u8> = Vec::new();
vec5.extend(vec6.drain(..4));
let mut vec9: std::vec::Vec<u8> = Vec::new();
return_vector().append(&mut vec9);
//won't get linted because it is not a vec
let mut heap = BinaryHeap::from(vec![1, 3]);
let mut heap2 = BinaryHeap::from(vec![]);
heap2.extend(heap.drain());
let mut x = vec![0, 1, 2, 3, 5];
let ref_x = &mut x;
let mut y = Vec::new();
y.append(ref_x);
}
fn return_vector() -> Vec<u8> {
let mut new_vector = vec![];
for i in 1..10 {
new_vector.push(i)
}
new_vector
}
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